$B (O H)_{3} + 2 H_{2} O ⇌ [B (O H)_{4}]^{-} + H_{3} O^{+}$
How can this reaction is made to proceed in forward direction?

addition of cis 1,2 diol

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addition of borax

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addition of trans, 1,2 diol

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addition of

N a_{2} H P O_{4}

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Solution

The correct option is A addition of cis 1,2 diol
The cis-diol forms a very stable complex with $[B (O H)_{4}]^{-}$ , removing it from the solution.
The reaction is reversible. Thus, the removal of one of the products shifts the equilibrium in the forward direction

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Similar questions

B (O H)_{3} + N a O H \to N a B O_{2} +

N a

[B (O H)_{4}] + H_{2} O

B (O H)_{3} + N a O H \to N a [B (O H)_{4}]

$B (O H)_{3} + N a O H ⇌ N a B O_{2} + N a [B (O H)_{4}]^{-} + H_{2} O$

How can the reaction above be made to proceed in the forward reaction?

B (O H)_{3} + N a O H \to N a [B (O H)_{4}]_{(a q)}

$B (O H)_{3} + N a O H ⇌ N a B O_{2} + N a [B (O H)_{4}]^{-} + H_{2} O$

How can the reaction above be made to proceed in the forward reaction?

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