$B (O H)_{3} + N a O H \to N a B O_{2} +$ $N a$ $[B (O H)_{4}] + H_{2} O$
How can this reaction is made to proceed in forward direction?

addition of cis 1, 2 diol

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addition of borax

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addition of trans 1, 2 diol

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addition of

N a_{2} H P O_{4}

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Solution

The correct option is D addition of cis 1, 2 diol
$B (O H)_{3} + N a O H \to N a B O_{2} + N a [B (O H)_{4}] + H_{2} O$
This reaction is made to proceed in the forward direction by the addition of cis 1, 2 diol.
$N a [B (O H)_{4}]$ forms a chelate compound with cis-1,2-diol and is removed from the equilibrium mixture.

Due to this, the reaction moves in the forward direction.

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Similar questions

$B (O H)_{3} + N a O H ⇌ N a B O_{2} + N a [B (O H)_{4}]^{-} + H_{2} O$

How can the reaction above be made to proceed in the forward reaction?

B (O H)_{3} + 2 H_{2} O ⇌ [B (O H)_{4}]^{-} + H_{3} O^{+}

B (O H)_{3} + N a O H \to N a [B (O H)_{4}]

$B (O H)_{3} + N a O H ⇌ N a B O_{2} + N a [B (O H)_{4}]^{-} + H_{2} O$

How can the reaction above be made to proceed in the forward reaction?

B (O H)_{3} + N a O H \to N a [B (O H)_{4}]_{(a q)}

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