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Question

[b×c c×a a×b]=

A
[a, b, c]
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B
2 [a, b, c]
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C
[a,b,c]2
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D
\N
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Solution

The correct option is C [a,b,c]2
[a×b b×c c×a]=(a×b).(b×c)×(c×a)
=(a×b).{[(b×c).a]c[(b×c).c]a}=(a×b).{[a.(b×c)]c[b,c,c]a}=(a×b).{[a,b,c]c0}=[a,b,c]{(a×b).c}=[a,b,c]2

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