Question 59 (b)
What should be added to 3pq+5p2q2+p3 to get p3+2p2q2+4pq?
In order to find the solution, subtract 3pq+5p2q2+p3 from p3+2p2q2+4pq.
Required expression is
p3+2p2q2+4pq−(3pq+5p2q2+p3)=p3+2p2q2+4pq−3pq−5p2q2−p3
On combining the like terms.
=p3−p3+2p2q2−5p2q2+4pq−3pq=−3p2q2+pq
So, if we add −3p2q2+pq in 3pq2+5p2q2+p3, we get p3+2p2q2+4pq