Complete the pattern:
$b a - c b - b - b a b -$

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Solution

Filling the pattern:
The series is $b a b c / b a b c / b a b c .$ Thus, the pattern $' b a b c'$ is repeated.
Hence, the series is $b a b c / b a b c / b a b c .$

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and

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, then

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∣ ∣ ∣ ∣ ∣ \begin{matrix} (b + c)^{2} & b a & a c b a & (c + a)^{2} & c b c a & c b & (a + b)^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣

is:

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Complete the pattern:ba-cb-b-bab-

Filling the pattern:The series is babc/babc/babc. Thus, the pattern 'babc' is repeated.Hence, the series is babc/babc/babc.

Complete the pattern:
$b a - c b - b - b a b -$

Filling the pattern:
The series is $b a b c / b a b c / b a b c .$ Thus, the pattern $' b a b c'$ is repeated.
Hence, the series is $b a b c / b a b c / b a b c .$