Question

$Ba(OH{)}_2+2N{H}_{4}Cl\to BaC{l}_2+2N{H}_3+X$

X is:

• A. $3H_{2}O$
• B. $H_{2}O$
• C. $2H_{2}O$
• D. $4H_{2}O$

Answer 1

The correct option is C $2H_{2}O$

$Ba(OH{)}_2+2N{H}_{4}CI⟶BaC{l}_2+2N{H}_3+2H_{2}O$

Above is the balanced reaction. Barium hydoxide has two oxygen atoms, so in product it gives two $H_{2}O$ molecule.