Question

$Ba(OH{)}_2$ is a strong base. The $pH$ of its 0.005 solution would be:

• A. 11.31
• B. 11.7
• C. 12
• D. none of these

Answer 1

Answer: (B)

11.7

$pH$ of $0.005M$ barium hydroxide
$pOH=-log\left(OH\right)$ to the base 10
$pOH=-log\left(0.005\right)=2.3$
$pH=14-pOH=14-2.3$
$pH=11.7$