$B a C l_{2} . n H_{2} O$ Barium chlorides crystals contain $14.8 %$ water of crystallization per molecule of barium chloride.

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Solution

Molecular mass of $B a C l_{2} . n H_{2} O$
$A t o m i c m a s s o f B a = 137 g A t o m i c m a s s o f C l = 35.5 g$
$M o l e c u l a r w e i g h t o f H_{2} O = 18 g$

$M o l e c u l a r w e i g h t o f B a C l_{2} . n H_{2} O = [208 + 18 n]$
$[208 + 18 n] c o n t a i n s w a t e r = 14.8 % w a t e r i n B a C l_{2} . n H_{2} O$
$[208 + 18 n] c o n t a i n s w a t e r = [208 + 18 n] \times \frac{14.8}{100} = 18 n$
$3078 + 266 n = 1800 n$
$3078 = 1534 n n = 2$
Thus, $2$ molecules of water of crystallization are present in $1$ molecule of $B a C l . n H_{2} O$ .

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Barium chloride crystals contain 14.8% water of crystallisation. Find the number of molecules of water of crystallisation per molecule.

barium chloride crystals contain 14.8% water of crystallisation.find the number of molecules of water of crystallisation per molecule.

B a C l_{2}

{100.0832}^{o}

K_{b}

0.52 K k g m o l^{- 1}

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