Balance the following chemical equations :

(a) $F e S O_{4}$ $H e a t ⟶$ $F e_{2} O_{3} + S O_{2} + S O_{3}$

(b) $P b (N O_{3})_{2} (s)$ $H e a t ⟶$ $P b O (s) + N O_{2} (g) + O_{2} (g)$

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Solution

(a)

Just giving the coefficient 2 to $F e S O_{4}$ balances the equation.

(b)

Now balance the number of N atoms by giving coefficient 2 in RHS to $N O_{2}$ . Then balance the number of oxygen required.

Now multiplying the whole equation by 2, we get

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