CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Balance the following redox reactions in acidic solutions:

UO2+Cr2O27UO2+2+Cr2++H2O

A
3UO2+Cr2O27+14H+3UO2+2+2Cr2++7H2O
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2UO2+2Cr2O27+14H+3UO2+2+2Cr2++5H2O
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3UO2+2Cr2O27+14H+3UO2+2+2Cr2++5H2O
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3UO2+Cr2O27+14H+3UO2+2+2Cr2++7H2O
The unbalanced chemical equation is as follows:
UO2+Cr2O27UO2+2+Cr3++H2O
Balance all atoms except H and O.
UO2+Cr2O27UO2+2+2Cr3++H2O
The oxidation number of U changes from +4 to +6. The change in the oxidation number is 2.
The oxidation number of Cr changes from +6 to +3. The change in the oxidation number per Cr atom is 3. Total change in the oxidation number for 2 Cr atoms is 6
To balance the increase in the oxidation number with decrease in oxidation number, multiply UO2 and UO2+2 with 3.
3UO2+Cr2O273UO2+2+2Cr3++H2O
T
o balance O atoms, add 6 water molecules of RHS.
3UO2+Cr2O273UO2+2+2Cr3++7H2O
To balance H atoms, add 14 H+ on LHS
3UO2+Cr2O27+14H+3UO2+2+2Cr3++7H2O
This is the balanced chemical equation.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Balancing_oxidation number
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon