Question

Balance the following unbalanced equations:

${\mathrm{N}}_2+{\mathrm{H}}_2\to {\mathrm{NH}}_3$

Answer 1

Steps involved in balancing a chemical reaction:

Step 1: Write the unbalanced equation.

${\mathrm{N}}_2+{\mathrm{H}}_2\to {\mathrm{NH}}_3$

Step 2: Write down the number of atoms of each elements present on both reactant as well as product side.

Element Reactant side Product side

$\mathrm{N}$ $2$ $1$

$\mathrm{H}$ $2$ $3$

Step 3: Add coefficients to balance the number of atoms on both the sides

Firstly balance $\mathrm{N}$ at product side by adding $2$ before ${\mathrm{NH}}_3$.

${\mathrm{N}}_2+{\mathrm{H}}_2\to 2{\mathrm{NH}}_3$

Secondly balance $\mathrm{H}$ at reactant side by adding $3$ before ${\mathrm{H}}_2$.

${\mathrm{N}}_2+3{\mathrm{H}}_2\to 2{\mathrm{NH}}_3$

The balanced equation is:

${\mathrm{N}}_2\left(\mathrm{g}\right)+3{\mathrm{H}}_2\left(\mathrm{g}\right)\to 2{\mathrm{NH}}_3\left(\mathrm{g}\right)$

Nitrogen Hydrogen Ammonia