Balancing the following chemical reactions by identifying the products
(a) CuSO₄ $+$ +HI $\to$ →CuI₂ $+$ +_-------

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Solution

CuSO₄ (aq) + 2 HI (aq) $\to$ CuI₂ (ppt) + H₂SO₄(aq)
This reaction is a double displacement reaction.
A double displacement reaction is a chemical reaction in which the radicals of the compounds are being interchanged.
Cupric sulphate combines with hydrogen iodide to form cupric iodide and sulphuric acid.
Cupric iodide is a light brown insoluble substance.
The insoluble substance formed is called a precipitate.
A double displacement reaction in which one of the products formed is an insoluble substance, then the reaction is called a precipitation reaction
The balanced chemical equation is .CuSO₄ (aq) + 2 HI (aq) $\to$ CuI₂ (ppt) + H₂SO₄(aq).

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^{'} P^{'}

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{C u S O}_{4}

\to

{C u I}_{2}

{C u I}_{2}

\to

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