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Question

Ball A of mass 10 kg moving with a velocity 6 m/s, collides with ball B of mass 50 kg which is at rest. What is the ratio of the kinetic energies of the ball A before and after the collision?

A
9:4
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B
4:9
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C
2:3
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D
3:2
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Solution

The correct option is A 9:4
Given:
ma=10 kg,ua=6 m/s
mb=50 kg,ub=0 m/s
Let velocity of ma is va after elastic collision.
va=(mambma+mb)ua+2mbubma+mb
=(105010+50)6+2×50×010+50 =4 m/s

The ratio of initial and final kinetic energies of block A is given by,
K.EiK.Ef=12mu2a12mv2a=12m×6212m×(4)2=3616=94
Hence the correct option is (a).

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