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Question

Balls of masses 4 kg and 10 kg are moving towards each other with speeds 6 m/s and 3 m/s respectively on a frictionless surface. After collision, the 4 kg ball is observed to return back (towards left) with speed 2 m/s. Find the velocity of 10 kg ball after collision.

A
2 m/s
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B
0.2 m/s
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C
9 m/s
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D
1 m/s
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Solution

The correct option is B 0.2 m/s
Given,
m1=4 kg;m2=10 kg
u1=6 m/s;u2=3 m/s
v1=2 m/s
(taking rightward +ve)
Let velocity of m2 after collision be v2=v m/s

Using principle of conservation of linear momentum,
m1u1+m2u2=m1v1+m2v2
4(6)+10(3)=4(2)+10(v)
v=0.2 m/s (towards right)

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