Question

Base area and volume of a solid right circular cylinder are $13.86sq.cm$ and $69.3cu.cm$ respectively. Find the height and curved surface area. (Take $\pi =\frac{22}{7}$)

Answer 1

Let $A$ and $V$ be the base area and volume of the solid right circular cylinder respectively.

Given that the base area $A=\pi r^2=13.86sq.cm$ and

volume, $V=\pi r^{2}h=69.3$

Thus, $\pi r^{2}h=69.3$

$\Rightarrow 13.86\times h=69.3$

$\therefore h=\frac{69.3}{13.86}=5cm$

Now the base area $=\pi r^2=13.86$

$\frac{22}{7}\times r^2=13.86$

$r^2=13.86\times \frac{7}{22}=4.41\Rightarrow r=\sqrt{4.41}=2.1cm$

Now, Curved Surface area, $CSA=2\pi rh$

$=2\times \frac{22}{7}\times 2.1\times 5$

Thus, $CSA=66sq.cm$.