Question

Base of a triangle is 9 cm and the height is 5 cm. Base of another triangle is 10 cm and height is 6 cm. Find the ratio of areas of these triangles.

Answer 1

Given:
Base and height of $triangl{e}_1$,
$b_1$ = 9 cm, $h_1$ = 5 cm.

Base and height of $triangl{e}_2$,
$b_2$ = 10 cm, $h_2$ = 6 cm.

Area of a triangle
$=\frac{1}{2}\times b\times h$

Ratio of areas of the triangles
$=\frac{b_1{h}_1}{b_2{h}_2}$

$=\frac{9\times 5}{10\times 6}$

$=\frac{3}{4}$