_ bbca _ bcca _ ac _ a _ cb

abeba

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acbab

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bacab

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bcaajb

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Solution

The correct option is C acbab
The series is abbc/ac/bcca/ba/caab/cb.

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Similar questions

$∣ ∣ ∣ ∣ ∣ \begin{matrix} a^{2} + 1 & a b & a c a b & b^{2} + 1 & b c c a & c b & c^{2} + 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = 1 + a^{2} + b^{2} + c^{2}$

A . . . . . . B B C . . . . A A B . . . . . C C A . . . . . B B C C

_ bbca _ bcca _ ac _ a _ cb

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