You visited us 1 times! Enjoying our articles? Unlock Full Access!

Derivation of Kp and Kc

Be2C+4H2O⟶ 2X...

Question

${B e}_{2} C + 4 H_{2} O ⟶ 2 X + {C H}_{4}$
$X + 2 O H ⟶ Y$
(X) and (Y) formed in the above two reactions are :

{B e C O}_{3}

and

B e {(O H)}_{2}

respectively

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B e {(O H)}_{2}

and

{B e C l}_{2}

respectively

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B e {(O H)}_{2}

and

{[B e {(O H)}_{4}]}_{4}^{2 -}

respectively

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{[B e {(O H)}_{4}]}_{4}^{2 -}

and

{B e C l}_{2}

respectively

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $B e {(O H)}_{2}$ and ${[B e {(O H)}_{4}]}_{4}^{2 -}$ respectively
The reaction involved are-
$B e_{2} C + 4 H_{2} O \to 2 B e (O H)_{2} + C H_{4}$
Hence X is $B e (O H)_{2}$
Now,
$B e (O H)_{2} + 2 O H^{-} \to [B e (O H)_{4}]^{2 -}$
So, Y is $[B e (O H)_{4}]^{2 -}$

Suggest Corrections

Similar questions

B e_{2} C + H_{2} O \to B e (O H)_{2} + X

C a C_{2} + H_{2} O \to C a (O H)_{2} + Y

X

Y

B e_{2} C + H_{2} O \to B e (O H)_{2} + x

C a C_{2} + H_{2} O \to C a (O H)_{2} + y

B e (O H)_{2}

B e (O H)_{2}

Read the above assertion and reason and choose the correct statement regarding it.

C H_{4}

B e C l_{2}

B e C l_{2}

B e C l_{2} + 2 H_{2} O \to B e (O H)_{2} + 2 H C l

H C l

Join BYJU'S Learning Program