Question

Be and N has extremely low value of EA against the trend. Explain.

Answer 1

$Be⟶1s^{2}2s^2$

$N⟶1s^{2}2s^{2}2p^3$

Both of them are present in the stable form.

$\therefore$ addition or removal of $e^{-}$ in these stable element is difficult. Hence they have low value (less negative value) of $EA$ value.