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Question

Be is an element which is invariable bivalent and whose oxide is soluble in excess of ____ and its dipostive ion has a noble gas core.

A
NaOH
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B
HCl
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C
NaCl
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D
noneofthese
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Solution

The correct option is D NaOH
The electronic configuration of Be is 1s22s2 or [He]2s2. It loses its two valence electrons to form Be2+ with electronic configuration 1s2 or [He].

BeO(s)+2NaOH(aq)+H2O(l)Na2Be(OH)4(aq)

Hence, Be is an element which is invariable bivalent and whose oxide is soluble in excess of NaOH and its dipostive ion has a noble gas core.

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