The correct options are
B Compound E when treated with an alkaline solution of K2HgI4 gives brown precipitate
C Compound D is NH3
D Compound E upon reacting with NaOH gives compound D as one of the products
Bedry air/Δ⟶BeO+Be3N2
Be3N2H2O⟶Be(OH)2+NH3
NH3HCl⟶NH4ClΔ⟶NH3+HCl
(a) A and B are BeO and Be3N2 respectively
(b) It is Nessler's reagent (K2HgI4) and is used as a test for ammonium ion detection:
NH+4+2[HgI4]2−+4OH−⟶HgO.Hg(NH2).IBrown ppt+7I−+3H2O
(c) Compound D is NH3
(d) NH4Cl+NaOH⟶NH3+H2O+NaCl