Beaker ‘A’ contains $C u S O_{4}$ solution and zinc pieces. Beaker ‘B’ contains $Z n S O_{4}$ solution and copper pieces. Chemical reaction will take place in -

Both the beakers ‘A’ and ‘B’

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Beaker ‘A’

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Beaker ‘B’

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In none of the beakers

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Solution

The correct option is B
Beaker ‘A’

The element Zn is higher than Cu in the reactivity series, i.e., Zn is more active than Cu. Therefore, Zn displaces the Cu ions in $C u S O_{4}$ to form a stable compound $Z n S O_{4}$ and Cu gets deposited at the bottom of the beaker.

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Beaker ‘A’ contains CuSO4 solution and zinc pieces. Beaker ‘B’ contains ZnSO4 solution and copper pieces. Chemical reaction will take place in -

The correct option is B Beaker ‘A’ The element Zn is higher than Cu in the reactivity series, i.e., Zn is more active than Cu. Therefore, Zn displaces the Cu ions in CuSO4 to form a stable compound ZnSO4 and Cu gets deposited at the bottom of the beaker.

Beaker ‘A’ contains $C u S O_{4}$ solution and zinc pieces. Beaker ‘B’ contains $Z n S O_{4}$ solution and copper pieces. Chemical reaction will take place in -

The correct option is B
Beaker ‘A’

The element Zn is higher than Cu in the reactivity series, i.e., Zn is more active than Cu. Therefore, Zn displaces the Cu ions in $C u S O_{4}$ to form a stable compound $Z n S O_{4}$ and Cu gets deposited at the bottom of the beaker.