Question

Beakers A, B, and C contain zinc sulphate, silver nitrate, and ferrous sulphate solutions respectively. Copper pieces are added to each beaker. Blue colour solution will appear in case of beaker:

• A. C
• B. B
• C. B & C
• D. A & C

Answer 1

The correct option is B B

A more reactive metal can replace a lesser reactive metal from its salt solution. However, the vice versa isn't quite possible.

Copper being a less reactive metal than zinc and iron cannot replace them from their respective salt solution. On the other hand, copper is more reactive than silver and hence, displaces silver from its salt solution.

${\text{2AgNO}}_3\left(aq\right)+\text{Cu}\left(s\right)\to {\text{Cu(NO}}_3{)}_2\left(aq\right)+\text{2Ag}\left(s\right)$

Hence, blue colour solution (Copper nitrate) will be formed in the beaker B.