- Isotope Relative Abudance- Atomic Massamu- 12C 98-892 12- 13C 1-108 13-00335- 14C 2 - 10-10 14-00317- -From the data given in the table- calculate the average atomic mass of C-

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Question

$\begin{matrix} I s o t o p e & R e l a t i v e A b u d a n c e (%) & A t o m i c M a s s (a m u)^{12} C & 98.892 & 12^{13} C & 1.108 & 13.00335^{14} C & 2 \times 10^{- 10} & 14.00317 \end{matrix}$
From the data given in the table, calculate the average atomic mass of C.

13 u

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12.011 u

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12.001 u

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12.0011 u

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Solution

The correct option is B 12.011 u
Average atomic mass is the weighted average of atomic mass of all the isotopes.

Contribution by each isotope = Relative abundance $\times$ Atomic mass

Contribution by
$_{6}^{12} C$ = (0.98892)(12)/100 = 11.86704
$_{6}^{13} C$ = (0.01108)(13.00335)/100 = 0.14407712

$_{6}^{14} C$ = (2 $\times$ $10^{- 10}$ )(14.003170/100 = 28.00634 $\times$ $10^{- 12}$

$∴$ Average atomic mass = sum of all contribution = 12.011 u

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$\begin{matrix} I s o t o p e & R e l a t i v e A b u d a n c e (%) & A t o m i c M a s s (a m u)^{12} C & 98.892 & 12^{13} C & 1.108 & 13.00335^{14} C & 2 \times 10^{- 10} & 14.00317 \end{matrix}$

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$\begin{matrix} Isotope & Relative Abudance (%) & Atomic Mass(amu)^{12} C & 98.892 & 12^{13} C & 1.108 & 13.00335^{14} C & 2 \times 10^{- 10} & 14.00317 \end{matrix}$

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IsotopeRelative Abudance(%)Atomic Mass(amu)12C98.8921213C1.10813.0033514C2×10−1014.00317 From the data given in the table, calculate the average atomic mass of C.

$\begin{matrix} I s o t o p e & R e l a t i v e A b u d a n c e (%) & A t o m i c M a s s (a m u)^{12} C & 98.892 & 12^{13} C & 1.108 & 13.00335^{14} C & 2 \times 10^{- 10} & 14.00317 \end{matrix}$
From the data given in the table, calculate the average atomic mass of C.