Question

$\begin{array}{cc}\text{List - I}& \text{List - II}\\ \text{(Compound)}& \text{(Hybridisation)}\\ \text{(I)}\left[Fe\right(EDTA){]}^{-}& \text{(P)}s{p}^3{d}^2\\ \text{(II)}\left[Ni\right(CN{)}_4{]}^{2-}& \text{(Q)}s{p}^3\\ \text{(III)}[CuC{l}_4{]}^{2-}& \text{(R)}{d}^{3}s\\ \text{(IV)}\left[Fe\right(H_{2}O{)}_6{]}^{2+}& \text{(S)}{d}^{2}s{p}^3\\ & \text{(T)}ds{p}^2\\ & \text{(U)}s{p}^{3}d\end{array}$

Which of the following option has correct combination considering List-I and List-II?

• A. $II\to R;IV\to P$
• B. $II\to T;IV\to P$
• C. $II\to Q;IV\to S$
• D. $II\to T;IV\to S$

Answer 1

The correct option is B $II\to T;IV\to P$

(II) Here $Ni$ is in $+2$ oxidation state having $\left[Ar\right]3d^8$ configuration.
$CN$ is a strong field ligand which causes pairing of electrons.

(IV) Here $Fe$ is in $+2$ oxidation state having $\left[Ar\right]3d^6$ configuration.
$H_{2}O$ is a weak field ligand which does not induce pairing of electrons.