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Byju's Answer
Standard XIII
Chemistry
Coordination Polyhedra
[ ...
Question
Column - I
Column - II
i
.
[
N
i
(
C
O
)
4
]
Planar octahedral, diamagnetic
i
i
.
[
F
e
(
N
O
)
(
H
2
O
)
5
]
2
+
Planar, paramagnetic
i
i
i
.
[
C
o
(
N
O
2
)
6
]
3
−
Octahedral, diamagnetic
i
v
.
[
C
u
(
N
H
3
)
4
]
2
+
Planar octahedral, paramagnetic
Octahedral, paramagnetic
A
i
−
r
,
i
i
−
p
,
i
i
i
−
q
,
i
v
−
t
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B
i
−
r
,
i
i
−
s
,
i
i
i
−
q
,
i
v
−
t
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C
i
−
r
,
i
i
−
s
,
i
i
i
−
p
,
i
v
−
q
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D
i
−
r
,
i
i
−
p
,
i
i
i
−
s
,
i
v
−
q
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Solution
The correct option is
C
i
−
r
,
i
i
−
s
,
i
i
i
−
p
,
i
v
−
q
Column -I
Column-II
i)
[
N
i
(
C
O
)
4
]
r)
Octahedral, diamagnetic
ii)
[
F
e
(
N
O
)
(
H
2
O
)
5
]
2
+
s)
Planar octahedral, paramagnetic
iii)
[
C
o
(
N
O
2
)
6
]
3
−
p)
Planar octahedral, diamagnetic
iv)
[
C
u
(
N
H
3
)
4
]
2
+
q)
Planar, paramagnetic
So the correct answer is
i
−
r
,
i
i
−
s
,
i
i
i
−
p
,
i
v
−
q
Suggest Corrections
0
Similar questions
Q.
Match Column I with Column II.
Column - I
Column - II
(Complex ion)
(CFSE and hybridisation)
a
.
[
C
r
(
N
H
3
)
6
]
3
+
(
P
)
0.0
Δ
0
,
s
p
3
d
2
−
hybridisation
b
.
[
C
u
(
N
H
3
)
6
]
2
+
(
Q
)
−
0.6
Δ
0
,
s
p
3
d
2
−
hybridisation
c
.
[
F
e
(
H
2
O
)
6
]
3
+
(
R
)
−
1.2
Δ
0
,
d
2
s
p
3
−
hybridisation
d
.
[
I
r
F
6
]
3
−
(
S
)
Diamagnetic
(
T
)
Paramagnetic
Q.
Column-1 represents the formula of the complex.
Column-2 represents the hybridization state of the complex and
Column-3 represents the nature of the complex.
C
o
l
u
m
n
I
C
o
l
u
m
n
2
C
o
l
u
m
n
3
(
I
)
[
N
i
(
C
O
)
4
]
(
i
)
s
p
3
(
P
)
D
i
a
m
a
g
n
e
t
i
c
(
H
i
g
h
s
p
i
n
)
(
I
I
)
[
P
t
C
l
4
]
2
−
(
i
i
)
s
p
3
d
2
(
Q
)
P
a
r
a
m
a
g
n
e
t
i
c
(
H
i
g
h
s
p
i
n
)
(
I
I
I
)
[
N
i
(
C
O
)
4
]
(
i
i
i
)
d
s
p
2
(
R
)
D
i
a
m
a
g
n
e
t
i
c
(
L
o
w
s
p
i
n
)
(
I
V
)
K
2
[
C
o
(
C
N
)
4
]
(
i
v
)
d
2
s
p
3
(
S
)
P
a
r
a
m
a
g
n
e
t
i
c
(
L
o
w
s
p
i
n
)
Which of the following set is correct for a diamagnetic tetrahedral complex?
Q.
Amongst
N
i
(
C
O
)
4
,
[
N
i
(
C
N
)
4
]
2
−
and
N
i
C
l
2
−
4
:
Q.
Copper(l) is diamagnetic where as copper (ll) is paramagnetic. Why?
Q.
[NiCl
4
]
2−
is paramagnetic while [Ni(CO)
4
] is diamagnetic though both are tetrahedral. Why?