A+HClO4⟶B+C(Filtrate)(mixoftwowhiteppt↓NaOHcation)Brownppt←−−−−−−−−K2Hgl4/OH−D The cations present in A are :
A
K+ and Na+
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B
K+ and NH+4
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C
NH+4 and Fe2+
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D
Mg2+ and Na+
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Solution
The correct option is BK+ and NH+4 Option (B) is correct. The cations present in A are K+ and NH+4. (K++NH+4)HClO4−−−−→KClO4↓+NH+4MixtureoftwoWhitecations(A)(B)(C)Δ↓NaOHHgO⋅Hg(NH2)I↓K2[HgI4]←−−−−−KOHNH3↑(Brownppt.)(D)