BA−AB 1B
A =_____ and B =_____
Since result is positive; BA > AB or B > A.
If B > A, to subtract B from A; we will have to borrow '1' from B.
BA (B-1) 1A
- AB - A B
_____ _________
1 B 1 B
∴ Now, we have
1A - B = B
10 + A - B = B
10 + A = 2B ____(1)
In second column, we have
B - 1 - A = 1
or B - A = 2 ____(2)
From equation (2), we get the possible values as shown below
AB0213243546576879
The set of values that satisfies equation (1) are A = 6 and B = 8.
So, A = 6 and B = 8.