$\begin{matrix} B O_{3}^{3 -} + c o n c . H_{2} S O_{4} + C H_{3} - C H_{2} - O H i g n i t e - -- \to & (A) G r e e n f l a m e \end{matrix}$
What is the oxidation number of central atom that is responsible for green flame in compound (A) ?

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Solution

$B_{3}^{3 -} + conc \cdot H_{2} S O_{4} + C H_{3} - C H_{2} - O H ignite ⟶ B {(C_{2} H_{5} O)}_{3} (A)$

This gives green flame due to boron,

$(- 1) \times 3 + x = 0$

$x = 3$

$Oxidation no. of boron = 3$

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