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Question

(xbxc)(b+c−a).(xcxa)(c+a−b).x(xaxb)(a+b−c)=?

A
xabc
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B
1
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C
xab+bc+ca
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D
xa+b+c
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Solution

The correct option is B 1
Give Exp. = x(bc)(b+ca).x(ca)(c+ab).x(ab)(a+bc)
=x(bc)(b+c)a(bc).x(ca)(c+a)b(ca).x(ab)(a+b)c(ab)
=x(b2c2+c2a2+a2b2).xa(b+c)b(ca)c(ab)
=(x0×x0)
=(1×1)=1.

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