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B
1
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C
xab+bc+ca
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D
xa+b+c
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Solution
The correct option is B1 Give Exp. = x(b−c)(b+c−a).x(c−a)(c+a−b).x(a−b)(a+b−c) =x(b−c)(b+c)−a(b−c).x(c−a)(c+a)−b(c−a).x(a−b)(a+b)−c(a−b) =x(b2−c2+c2−a2+a2−b2).x−a(b+c)−b(c−a)−c(a−b) =(x0×x0) =(1×1)=1.