Question

$\left(\begin{array}{c}\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}}\end{array}\right)÷\sqrt{\frac{16}{81}}=$ ?

• A. $\frac{1}{48}$
• B. $\frac{5}{48}$
• C. $\frac{5}{16}$
• D. $\frac{1}{16}$

Answer 1

Answer: (C)

$\frac{5}{16}$

$(\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}})÷\sqrt{\frac{16}{81}}=(\frac{15}{27}-\frac{5}{12})÷\frac{4}{9}=\frac{5\times 9}{36\times 4}=\frac{5}{16}$