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Question

∣ ∣112302102∣ ∣

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Solution

M11=0 M12=11 M13=0 M21=0 M22=1 M23=1 M31=2 M32=8 M33=3 C11=0 C12=11 C13=0 C21=3 C22=1 C23=1 C31=2 C32=8 C33=3
co factor matrix 0110311+283
AdjA=03+21118013,|A|=0+1=11
A.AdjA=11230210303+21118013,|A|
=110001100011=100010001=11I=|A|I
Adj.A.A=03+21118013,|A|=112302103=110001100011
=11110001100011=11×I=|A|I
A.AdjA=Adj.A.A=|A|I

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