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Question

Below is a grouped data distribution for which mean is to be found by step deviation method.

Class IntervalNumber of Frequency(fi)Class mark(xi)di=xiaui=dih01004050200D......10020039150B.....E.....200300342500030040030350100140050045450C.....F......TotalA.fi=......

Find the value of A, B, C, D, E and F respectively.


A

188 , -100, 200, -2 ,-1 and 2

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B

186 , 100, -200, -2 ,-1 and 2

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C

188 , 100, -200, 2 ,-1 and -2

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D

186 , -100, -200, -2 ,-1 and 2

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Solution

The correct option is A

188 , -100, 200, -2 ,-1 and 2


fi= sum of frequencies of each class = 40 + 39 + 34 + 30 + 45 = 188

di = xi - a

where xi = ith class mark

a = assumed mean

Using above formula for 1st class(0-100) we get-

-200 = 50 – a

a = 250

Using above formula for 2nd class(100-200) we get-

B = 150 – 250

B = -100

Similarly, C = 200.

ui = (di)h

Here h = class interval = 100. h is constant.

For 1st class(0-100),

u1 = d1h= -200100 = -2

Thus, D = -2

Similarly E = -1, F = 2

Answers are 188 , -100, 200, -2 ,-1 and 2


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