Below is a grouped data distribution for which mean is to be found by step deviation method.
Class IntervalNumber of Frequency(fi)Class mark(xi)di=xi−aui=dih0−1004050−200D......100−20039150B.....E.....200−3003425000300−400303501001400−50045450C.....F......TotalA.∑fi=......
Find the value of A, B, C, D, E and F respectively.
188 , -100, 200, -2 ,-1 and 2
∑fi= sum of frequencies of each class = 40 + 39 + 34 + 30 + 45 = 188
di = xi - a
where xi = ith class mark
a = assumed mean
Using above formula for 1st class(0-100) we get-
-200 = 50 – a
a = 250
Using above formula for 2nd class(100-200) we get-
B = 150 – 250
B = -100
Similarly, C = 200.
ui = (di)h
Here h = class interval = 100. h is constant.
For 1st class(0-100),
u1 = d1h= -200100 = -2
Thus, D = -2
Similarly E = -1, F = 2
Answers are 188 , -100, 200, -2 ,-1 and 2