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Standard XII

Physics

Electric Field Due to a Line of Charge Not on Its Axis

Between two p...

Question

Between two plates charged to 10q there is an electric field $E$ , what acceleration will a positively charged particle, with a charge of $q$ and a mass of $m$ , experience in this region, due only the electric field?

\frac{21 q E}{m}

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\frac{11 q E}{m}

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\frac{10 q E}{m}

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\frac{q E}{m}

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Solution

The correct option is D $\frac{q E}{m}$
The electric field between two charged plates charged to $10 q$ is $E = \frac{V}{d} = \frac{10 q}{A ϵ_{0}}$
The force experienced by a charged particle in the region= $q E$
Hence the acceleration of charge of mass $m = \frac{F}{m} = \frac{q E}{m}$
Correct answer is option D.

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Between two plates charged to 10q there is an electric field E, what acceleration will a positively charged particle, with a charge of q and a mass of m, experience in this region, due only the electric field?

The correct option is D qEmThe electric field between two charged plates charged to 10q is E=Vd=10qAϵ0The force experienced by a charged particle in the region=qEHence the acceleration of charge of mass m=Fm=qEmCorrect answer is option D.

Between two plates charged to 10q there is an electric field $E$ , what acceleration will a positively charged particle, with a charge of $q$ and a mass of $m$ , experience in this region, due only the electric field?