Question

Binding energy per nucleon for $C^{12}$ is 7.68 MeV and that for $C^{13}$ is 7.5 MeV. If energy required to remove a neutron from $C^{13}$ is $xMeV$, then $x$ is (Write upto two digits after the decimal point.)

Answer 1

B.E. of $C^{12}$ is $E_{C_{12}}=7.68\times 12MeV$

B.E. of $C^{13}$ is $E_{C_{13}}=7.5\times 13MeV$

Energy to remove neutron is $=(7.5\times 13-7.68\times 12)$

$=5.34MeV$