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Question

Block B of mass 2 kg is placed on smooth horizontal plane. Block A of mass 1 kg is placed on block B. The coefficient of friction between A and B is 0.40. The block A is imparted a velocity 16 m/s at t = 0. Find the time at which momentum of the two blocks are equal (in seconds). (g=10 m/s2).

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Solution

P1=m1V1=(1)(16μgt) till velocities are equal.
P2=m2V2=(2)(μm1gm2)t=μ(1)gt till velocities are equal.
For P1=P2,16μgt=μgt
t=16(2)(0.4)(10)=2 sec

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