Block of mass 8 kg moving with a velocity of 36 kilometre per hour. If the velocity is reduced to 18 kilometre per hour in 0.5 seconds What is the retarding force on the

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Solution

Mass of the car = 8 kg

Initial velocity u = 36 km/hr = (1000/3600) x 36 = 10 m/s

Final velocity v = 18 km/hr = (1000/3600) x 18 = 5 m/s

Time t = 0.5 s

retardation a = (v-u)/t = (5-10)/0.5
= -10 m/s^2

retardation force = m x a = 8 x-10 = -80 N

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Block of mass 8 kg moving with a velocity of 36 kilometre per hour. If the velocity is reduced to 18 kilometre per hour in 0.5 seconds What is the retarding force on the

Mass of the car = 8 kg Initial velocity u = 36 km/hr = (1000/3600) x 36 = 10 m/s Final velocity v = 18 km/hr = (1000/3600) x 18 = 5 m/s Time t = 0.5 s retardation a = (v-u)/t = (5-10)/0.5 = -10 m/s^2 retardation force = m x a = 8 x-10 = -80 N

Mass of the car = 8 kg

Initial velocity u = 36 km/hr = (1000/3600) x 36 = 10 m/s

Final velocity v = 18 km/hr = (1000/3600) x 18 = 5 m/s

Time t = 0.5 s

retardation a = (v-u)/t = (5-10)/0.5
= -10 m/s^2

retardation force = m x a = 8 x-10 = -80 N