Bohr effects is the effects of :

C O_{2}

on haemoglobin

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C O_{2}

on oxyhaemoglobin

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C O_{2}

on RBCs

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O_{2}

on haemoglobin

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Solution

The correct option is A $C O_{2}$ on haemoglobin
Borh effects is the effect of $C O_{2}$ on hemoglobin (A option)

This effect explains how hydrogen ions and carbon dioxide effect the effinity of oxygen in Haemoglobin. If pH was lower than it normally was, then the haemoglobin does not bind $O_{2}$ as well.
The lower the pH, more hydrogen ions, the high $C O_{2}$ level and less affinity towards haemoglobin has for $O_{2}$ and vice versa.

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