Question

Bohr's quantised orbits correspond to de Broglie's electron waves in phase. How do you correlate the two?

Answer 1

In Bohr's orbit $mvr=\frac{nh}{2\pi }\left(I\right)$ i.e. it is quantised.

De broglie's electron wave $Z_n=\frac{h}{mv}.........\left(II\right)$

Standing wave condition : circumference=whole number of wavelengths

$2\pi r=n{Z}_n........\left(III\right)$

Putting $\left(III\right)$ in $\left(I\right)$ will get $\left(II\right)$

$Z_n=\frac{h}{mv}$