Question

Bombardment of aluminium by $\alpha$-particle leads to its artificial disintegration in two ways, (i) and (ii) as shown.
${}_{23}^{27}\text{Al}\stackrel{\left(ii\right)}{\to }{}_{15}^{30}\text{P}+Y$
(i)$\downarrow$
${}_{14}^{30}\text{Si}+X_{14}^{30}\text{Si}+Z$
Products X, Y and Z respectively are:

• A. proton, neutron, positron
• B. neutron, positron, proton
• C. proton, positron, neutron
• D. positron, proton, neutron

Answer 1

Answer: (A)

proton, neutron, positron

Balanced reactions are:
${}_{13}^{27}\text{Al}{+}_2^4\text{He}{⟶}_{14}^{30}\text{Si}{+}_1^1\text{p}\left(x\right),i.e.,proton$
${}_{13}^{27}\text{Al}{+}_2^4\text{He}{⟶}_{15}^{30}\text{P}{+}_0^{1}n\left(y\right),i.e.,neutron$
${}_{15}^{30}\text{P}{+}_{14}^{30}\text{Si}{⟶}_{+1}^0\text{e}\left(z\right),i.e.,positron$