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Lattice Structure of Ionic Compounds

bond angle is...

Question

bond angle is largest in OF2 , H2O , OCl2 , OBr2 write them in increasing order of bond angle?

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Solution

$H_{2} O > O B r_{2} > O C l_{2} > O F_{2} T h e r e a s o n i s m o r e t h e e l e c t r o n e g a t i v i t y l e s s w i l l b e t h e b o n d a n g l e . A m o n g t h e a t o m s O h a s t h e l o w e s t e l e c t r o n e g a t i v i t y . S o i t s b o n d a n g l e i s m o r e . A m o n g h a \log e n F h a s t h e h i g h e s t e l e c t r o n e g a t i v i t y t h a t i s w h y i t h a s l e s s b o n d a n g l e .$

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Similar questions

Q. The sequence that correctly represents the increasing order of bond angles in

O F_{2}, O C l_{2}, C l O_{2}

H_{2} O

I	II
$O C l_{2}$	$O F_{2}$

The bond angle is greater in

O C l_{2}

O F_{2}

because there is some

π

interactions in

O C l_{2}

involving donation from the filled p-orbitals on oxygen into the empty d-orbitals on chlorine No

π

-bonding is possible for

O F_{2}

because all orbitals are filled on both atoms.
If true enter 1, else enter 0.

Q. The bond angle in

O F_{2}

O F_{2}, C l_{2} O, B r_{2} O

is minimum. It is because in case of

O F_{2}

:

Q. Consider the following molecules :
(I)

H_{2} O

H_{2} S

H_{2} S e

H_{2} T e

Arrange these molecules in increasing order of bond angle.

Q. Arrange the molecules in the increasing order of bond angle.

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Lattice Structure of Ionic Compounds

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