Bond dissociation energy of CH3−H bond is 103kcalmol−1 and heat of formation of CH4(g) as −17.88kcalmol−1. The dissociation energy of H2(g) into H atoms is 103kcal/mol. The heat of formation of methyl radical is ?
A
3.61kcalmol−1
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B
−3.61kcalmol−1
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C
33.61kcalmol−1
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D
−33.61kcalmol−1
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Solution
The correct option is C33.61kcalmol−1 Given- BECH3−H=103kcalmol−1 & ΔHf=−17.88kcalmol−1
The required reaction is, CH4(g)→CH3(g)+H(atom,g)
=△Hf(CH3,g)+△Hf(Hatom,g)−△Hf(CH4,g) (△Hf)CH3,g=103−1032+(−17.889)=33.611kcalmol−1 ∴ Heat of formation of methyl radical is △H=33.611kcalmol−1