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Question
Bond dissociation energy of CH3−H bond is 103 kcal mol−1 and heat of formation of CH4(g) as −17.88 kcal mol−1. The dissociation energy of H2(g) into H atoms is 103 kcal/mol. The heat of formation of methyl radical is ?
Bond dissociation energy of CH3−H bond is 103 kcal mol−1 and heat of formation of CH4(g) as −17.88 kcal mol−1. The dissociation energy of H2(g) into H atoms is 103 kcal/mol. The heat of formation of methyl radical is ?
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Solution
The correct option is C 33.61 kcal mol−1
Given-
BECH3−H=103 kcal mol−1 &
ΔHf=−17.88 kcal mol−1
The required reaction is,
CH4(g)→CH3(g)+H(atom,g)
=△Hf(CH3,g)+△Hf(H atom,g)−△Hf(CH4,g)
(△Hf)CH3,g=103−1032+(−17.889)=33.611 kcal mol−1
∴ Heat of formation of methyl radical is △H=33.611 kcal mol−1
Given-
BECH3−H=103 kcal mol−1 &
ΔHf=−17.88 kcal mol−1
The required reaction is,
CH4(g)→CH3(g)+H(atom,g)
=△Hf(CH3,g)+△Hf(H atom,g)−△Hf(CH4,g)
(△Hf)CH3,g=103−1032+(−17.889)=33.611 kcal mol−1
∴ Heat of formation of methyl radical is △H=33.611 kcal mol−1
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