Bond distance C - H in CH 4 is x - A and that of Si - H in SiH 4 is y A - C - Si bond is z - A- Calculate covalent radii of H atom igonoring the electronegativity difference- A- x-y-z-2B- x-y-z-2C- x-22-z-2D- x-2-y-2

The correct option is B x+y z2Consider The radius of H atom = r_H ∘A The radius of C atom = r_C ∘A The radius of Si atom = r_Si ∘A Given bondlength of C H = ...

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Standard XII

Chemistry

Physical Properties of Boron Family

Bond distance...

Question

Bond distance $C - H$ in $C H_{4}$ is $x \circ A$ and that of $S i - H$ in $S i H_{4}$ is $y \circ A$ . $C - S i$ bond is $z \circ A$ . Calculate covalent radii of H atom igonoring the electronegativity difference.

\frac{x + y + z}{2}

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\frac{x + y - z}{2}

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\frac{x - y - z}{2}

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\frac{x + y}{2}

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Solution

The correct option is B $\frac{x + y - z}{2}$
Consider
The radius of H atom $= r_{H} \circ A$
The radius of C atom $= r_{C} \circ A$
The radius of Si atom $= r_{S i} \circ A$
Given bondlength of $C - H = x \circ A$
Bond length of $S i - H = y \circ A$
Bond length of $C - S i = z \circ A$
Value of bond length of C - H
$r_{H} + r_{C} = x - (i)$
Value of bond length of Si-H
$= r_{S i} + r_{H} = y - (i i)$
Value of bond length of C-Si
$= r_{C} + r_{S i} = z (i i i)$
Solving (i) (ii) and (iii)
Value of $r_{H} = \frac{x + y - z}{2} \circ A$

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Bond distance C−H in CH4 is x ∘A and that of Si−H in SiH4 is y ∘A. C−Si bond is z ∘A. Calculate covalent radii of H atom igonoring the electronegativity difference.

Bond distance $C - H$ in $C H_{4}$ is $x \circ A$ and that of $S i - H$ in $S i H_{4}$ is $y \circ A$ . $C - S i$ bond is $z \circ A$ . Calculate covalent radii of H atom igonoring the electronegativity difference.