H-H-Hx-C-H-yC-H-C-C- CZ-HGive the correct order of bond lengths x- y and z in-

The correct option is C x gt; y gt; z Option C is the answer. Order of bond length: x gt;y gt;z Order of s character: sp g ...

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Standard X

Chemistry

Covalent Bond vs Ionic Bond

H-H|Hx|C-H|yC...

Question

$H - H | C x | H - C | y H = H | C - C \equiv C Z - H$
Give the correct order of bond lengths $x, y$ and $z$ in:

x = y < z

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x = y > z

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x > y > z

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z > y > x

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Solution

The correct option is C $x > y > z$
Option C is the answer. Order of bond length:- $x > y > z$
Order of $s$ character:- $s p > s p^{2} > s p^{3}$
More the $s$ -character, more will be overlapping and stronger the bond, lesser the bond length.

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Similar questions

Q. Which of the following is the correct order for bond energy for

C - H

bonds in these compounds?

B_{2} H_{6} + N a \to X + Y

B_{2} H_{6} + N a B H_{4} \to Y + Z

Identify X, Y and Z.

$C_{6} H_{6} + C l_{2} F e l_{3} - - \to X + H C l C_{6} H_{6} + H N O_{3} H_{2} S O_{4} - --- \to < 60^{\circ} C Y + H_{2} O C_{6} H_{6} + C H_{3} C O C l A l C l_{3} - -- \to Z + H C l$

The correct order of reactivity of X, Y, Z towards electrophilic substituation reaction is

Q. Bond distance

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C H_{4}

x \circ A

and that of

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S i H_{4}

y \circ A

C - S i

bond is

z \circ A

. Calculate covalent radii of H atom igonoring the electronegativity difference.

Q. If

\frac{y}{b + c - a} = \frac{z}{c + a - b} = \frac{x}{a + b - c}

and

x + y + z \neq 0

, then which of the following hold true?

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H−H|Cx|H−C|yH=H|C−C≡CZ−HGive the correct order of bond lengths x, y and z in:

The correct option is C x>y>zOption C is the answer. Order of bond length:- x>y>zOrder of s character:- sp>sp2>sp3More the s-character, more will be overlapping and stronger the bond, lesser the bond length.

$H - H | C x | H - C | y H = H | C - C \equiv C Z - H$
Give the correct order of bond lengths $x, y$ and $z$ in:

The correct option is C $x > y > z$
Option C is the answer. Order of bond length:- $x > y > z$
Order of $s$ character:- $s p > s p^{2} > s p^{3}$
More the $s$ -character, more will be overlapping and stronger the bond, lesser the bond length.