Bond lengths of all the bonds between the central atom and the monovalent atom are equal in:

P C l_{5}

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P F_{5}

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B_{2} H_{6}

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I_{2} C l_{6}

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Solution

The correct option is B $P F_{5}$

$B_{2} H_{6}$ and $I_{2} C l_{6}$ both are dimerized molecules of $B H_{3}$ and $I C l_{3}$ respectively.

$B - H (b r i d g e d) b o n d l e n g t h = 131 p m$ & $B - H (t e r m i n a l) b o n d l e n g t h = 119 p m$ in $B_{2} H_{6}$

$I - C l (b r i d g e d) b o n d l e n g t h = 270 p m$ & $I - C l (t e r m i n a l) b o n d l e n g t h = 230 p m$ in $I_{2} C l_{6}$

$P C l_{5}$ has geometry trigonal bi-pyramidal and axial bonds are longer than equatorial bonds.

$P F_{5}$ shows Berry pseudorotation.

This is a type of vibration causing molecules of certain geometries to isomerise by the exchange of two axial ligands for two of the equatorial ligands.

In $P F_{5}$ axial bonds & equatorial bonds inter-conversion occurs rapidly as shown below.
Thus, all the bonds are of equal bond length.

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