Bond order of $B e_{2}$ is:

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Solution

The correct option is D 0
$B e_{2} (8) \to σ_{1 s^{2}} σ_{1 s^{2}}^{} σ_{2 s^{2}} σ_{2 s^{2}}^{}$
Bond Order(B.O) of $B e_{2} = \frac{1}{2} [4 - 4] = 0$

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Bond order of Be2 is:

The correct option is D 0Be2(8)→σ1s2σ∗1s2σ2s2σ∗2s2Bond Order(B.O) of Be2=12[4−4]=0

Bond order of $B e_{2}$ is:

The correct option is D 0
$B e_{2} (8) \to σ_{1 s^{2}} σ_{1 s^{2}}^{} σ_{2 s^{2}} σ_{2 s^{2}}^{}$
Bond Order(B.O) of $B e_{2} = \frac{1}{2} [4 - 4] = 0$