Bond order of He 2- He 2-and He 22- are respectively-A- 1- 1-2- 0B- 0- I -2- 1C- 1-2- 1-0D- 1-0- 1-2

The correct option is B 0, 1/2, 1Bond order (B.O.) =N_BMO N_ABMO/2 He_2 → (σ 1s)^2 (σ^*1s)^2 ∴B.O. =2 2/2=0/2=0 He_2^+→ (σ 1s)^2 (σ^*1s)^1 ∴B.O. =2 1/2=1/2 He_ ...

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Standard XII

Chemistry

Oxoacids of Halogens

Bond order of...

Question

Bond order of $H e_{2}, H e_{2}^{+}$ and $H e_{2}^{2 +}$ are respectively:

1, \frac{1}{2}, 0

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0, \frac{1}{2}, 1

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\frac{1}{2}, 1, 0

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1, 0, \frac{1}{2}

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Solution

The correct option is B $0, \frac{1}{2}, 1$
Bond order (B.O.) $= \frac{N_{B M O} - N_{A B M O}}{2}$
$H e_{2} \to (σ 1 s)^{2} (σ^{} 1 s)^{2}$
$∴$ B.O. $= \frac{2 - 2}{2} = \frac{0}{2} = 0$
$H e_{2}^{+} \to (σ 1 s)^{2} (σ^{} 1 s)^{1}$
$∴$ B.O. $= \frac{2 - 1}{2} = \frac{1}{2}$
$H e_{2}^{2 +} \to (σ 1 s)^{2} (σ^{*} 1 s)^{0}$
$∴$ B.O. $= \frac{2 - 0}{2} = 1$

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Bond order of He2,He+2 and He2+2 are respectively:

The correct option is B 0,12,1Bond order (B.O.) =NBMO−NABMO2 He2→(σ1s)2(σ∗1s)2 ∴B.O. =2−22=02=0 He+2→(σ1s)2(σ∗1s)1 ∴B.O. =2−12=12 He2+2→(σ1s)2(σ∗1s)0 ∴B.O. =2−02=1

Bond order of $H e_{2}, H e_{2}^{+}$ and $H e_{2}^{2 +}$ are respectively: