Borax is converted into crystalline boron by the following steps.

$B o r a x x ⟶ H_{3} B O_{3} H e a t ⟶ B_{2} O_{3} y ⟶ H e a t B$
X & Y are respectively

$H_{2} S O_{4}, A l$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$H_{2} S O_{4}, C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$H C l, M g$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$C, H C l$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$H_{2} S O_{4}, A l$

$N a_{2} B_{4} O_{7} + H_{2} S O_{4} + 5 H_{2} O \to N a_{2} S O_{4} + 4 H_{3} B O_{3}$
$2 H_{3} B O_{3} H e a t ⟶ B_{2} O_{3} + 3 H_{2} O$
$B_{2} O_{3} + 2 A l ⟶ 2 B + A l_{2} O_{3}$

Suggest Corrections

Similar questions

Borax is converted into crystalline boron by the following steps.

$B o r a x x ⟶ H_{3} B O_{3} H e a t ⟶ B_{2} O_{3} y ⟶ H e a t B$
X & Y are respectively

Q. Borax is converted into crystalline boron by the following steps:

B o r a x X \to H_{3} B O_{3} Δ \to B_{2} O_{3} Y - \to Δ B

Then

X

and

Y

are respectively:

Q. The following sequence of reactions are used to convert Borax into Boron.

N a_{2} [B_{4} O_{5} (O H)_{4}] .8 H_{2} O X - \to H_{3} B O_{3} △ - \to B_{2} O_{3} Y \to B B o r o n

Reagents X and Y are respectively:

Q. Amorphous boron is extracted from borax following steps :

B o r a x (A) \to H_{3} B O_{3} H e a t \to B_{2} O_{3} (B) \to B o r o n

(A)

and

(B)

are

Q. The following sequence of reactions are used to convert Borax into Boron.

N a_{2} [B_{4} O_{5} (O H)_{4}] .8 H_{2} O X - \to H_{3} B O_{3} △ - \to B_{2} O_{3} Y \to B B o r o n

Reagents X and Y are respectively:

Join BYJU'S Learning Program

Borax is converted into crystalline boron by the following steps. Boraxx⟶H3BO3Heat⟶B2O3y⟶HeatB X & Y are respectively

The correct option is A H2SO4, Al Na2B4O7 + H2SO4+5H2O→Na2SO4 + 4H3BO3 2H3BO3Heat⟶B2O3+3H2O B2O3+2Al⟶2B+Al2O3

Borax is converted into crystalline boron by the following steps.

$B o r a x x ⟶ H_{3} B O_{3} H e a t ⟶ B_{2} O_{3} y ⟶ H e a t B$
X & Y are respectively

The correct option is A
$H_{2} S O_{4}, A l$

$N a_{2} B_{4} O_{7} + H_{2} S O_{4} + 5 H_{2} O \to N a_{2} S O_{4} + 4 H_{3} B O_{3}$
$2 H_{3} B O_{3} H e a t ⟶ B_{2} O_{3} + 3 H_{2} O$
$B_{2} O_{3} + 2 A l ⟶ 2 B + A l_{2} O_{3}$