You visited us 4 times! Enjoying our articles? Unlock Full Access!

Preparation of Haloalkanes from Alcohol

Borax is prep...

Question

Borax is prepared by treating colemanite with :

N a N O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

NaCl

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a H C O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} C O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $N a_{2} C O_{3}$
Option (D) is correct.
Borax is prepared by treating colemanite with $N a_{2} C O_{3}$ .
$C a_{2} B_{6} O_{11} C o l e m a n i t e + 2 N a_{2} C O_{3} ⟶ N a_{2} B_{4} O_{7} b o r a x + 2 N a B O_{2} Sodium metaborate + 2 C a C O_{3} ↓$
Sodium metaborate is also converted to borax by passing carbon dioxide through it.
$4 N a B O_{2} + C O_{2} ⟶ N a_{2} B_{4} O_{7} + N a_{2} C O_{3}$

Suggest Corrections

Similar questions

N a_{2} C O_{3}

N a H C O_{3}

H C l

N a C l

c o n c . H_{2} S O_{4}

H I

N a I

c o n c . H_{2} S O_{4}

Na2CO3+Hcl,_______≥NaCL+NaHCO3. Na2CO3+HcL________≥NaCL+H2o+CO2 why is it written like that ,is this equation both write?

N a H C O_{3}

N a_{2} C O_{3}

H C l

15.0

11.0

N a C l

N a_{2} C O_{3}

N a_{2} C O_{3} + 2 H C l \to 2 N a C l + C O_{2} + H_{2} O

N a H C O_{3} + H C l \to N a C l + C O_{2} + H_{2} O

N a C l

N a H C O_{3}

N a_{2} C O_{3}

58.5

84

106

Join BYJU'S Learning Program